Now, Problem on ages can be categorized into three types, i.e.
When the digits are reversed, the number is increased by 27. I know it’s an easy one but still you should read it at least twice. Rearranging and simplifying the second equation in the form “y – x = 3” and solving both the equations we get, x = 2 and y = 5 Now let’s check once are we getting the right answer if x = 2 and y = 5 then the original no. But, today in this blog, we will be focused on only one type of problems i.e. These problems are very confusing and the language is a bit complex and we end up usually making up errors in the formulation of the equation.
So, I’ll discuss and try various different type of questions on this concept that will give you a thorough understanding of how to form Linear equations and solve them.
This is shown in the examples involving a single person.
If the age problem involves the ages of two or more people then using a table would be a good idea. In 20 years, Kayleen will be four times older than she is today.
Related Topics: More Algebra Word Problems How to solve Age Problems Involving A Single Person?
Write one of the equations so it is in the style "variable = ...": We can subtract x from both sides of x y = 8 to get y = 8 − x. Write one of the equations so it is in the style "variable = ...": Let's choose the last equation and the variable z: First, eliminate x from 2nd and 3rd equation.
Well, we can see where they cross, so it is already solved graphically. Let's use the second equation and the variable "y" (it looks the simplest equation). Now repeat the process, but just for the last 2 equations.
It’s been given the ratio between the present age of A and B is 5:3.
Thus, their present age would be 5x and 3x respectively.